The rate of hydrate formation for the given c | vedclass

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(C) The rate of hydrate formation depends on the electrophilicity of the carbonyl carbon. Greater electrophilicity leads to a faster rate of nucleophi

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$II > I > III$

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(C) The rate of hydrate formation depends on the electrophilicity of the carbonyl carbon. Greater electrophilicity leads to a faster rate of nucleophilic addition. Electrophilicity is decreased by electron-donating groups (like $-CH_3$) and increased by steric hindrance reduction. Compound $II$ is formaldehyde $(HCHO)$,which has no electron-donating groups and minimal steric hindrance. Compound $I$ is acetaldehyde $(CH_3CHO)$,which has one electron-donating methyl group. Compound $III$ is acetone $((CH_3)_2CO)$,which has two electron-donating methyl groups and greater steric hindrance. Therefore,the order of reactivity is $II > I > III$.

Column-$1$ (Reaction of carbonyl compound with)	Column-$2$ (Product)
$A$. Hydroxylamine	$I$. Hydrazone
$B$. Alcohol	$II$. Schiff's base (Substituted imine)
$C$. Hydrazine	$III$. Oxime
$D$. Amine	$IV$. Ketal

The rate of hydrate formation for the given compounds is:

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Match the following:
Column-$1$ (Reaction of carbonyl compound with) Column-$2$ (Product)
$A$. Hydroxylamine $I$. Hydrazone
$B$. Alcohol $II$. Schiff's base (Substituted imine)
$C$. Hydrazine $III$. Oxime
$D$. Amine $IV$. Ketal
The correct match is:

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